There are 12 Pink, 16 Brown and 20 black color caps in a box. If a cap is picked at random, what is the probability of having either a pink or a Black Cap?

Option 4 : 2/3

**Given:**

Black color caps = 20

Brown color caps = 16

Pink color caps = 12

**Formula Used:**

P(E1 or E2) = P(E1) + P(E2)

**Calculations:**

Let E_{1}, E_{2} be the event of picking a pink cap and black cap respectively.

Total no. of caps in a box = 12 + 16 + 20 = 48

E1 = 12 /48 = 1/4

E2 = 20 /48 = 5/12

P(E_{1} or E_{2}) = P(E_{1}) + P(E_{2})

P(E1 or E2) = 1/4 + 5/12

P(E1 or E2) = 2/3

Hence, 2/3 is the probability to select a pink or a black cap